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I have seen this question for bc, but how do you do this in dc? For example, if the command were q, I would want to use it like this:

10k
5q2q/

To compute log_2(5).

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Brian McCutchon
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1 Answers1

8

There's no built-in command for this in dc, but you can implement any of the numerical methods for computing a logarithm as macros.

For example, this one computes ln(x) using ln((1+y)/(1-y)) Taylor series expansion:

# L (x -- y)
# Natural logarithm of `x`.
[ 1-d2+/
  d2*Sk              # Initialize multiplier
  d*Sy               # Initialize multiplier factor
  0Ss                # Initialize accumulator
  10K^Sp             # Initialize 10^k power
  [ d1r/lk*ls+lsrdss   # Update accumulator
    -lp*d*1 [s_q]s_>_  # Check precision
    lkly*sk 2+         # Update multiplier and counter
    lfx
  ]Sf
  1lfxLs
LkLyLpLfs_s_s_s_] sL

Use it like this:

10k
5lLx 2lLx /p

It's not optimal, in particular for large numbers (x ≫ 1), but a method with a faster convergence can also be implemented this way, if needed.

Squeezed version (somewhat faster):

[1-d2+/d2*Skd*Sy0Ss10K^Sp[d1r/lk*ls+lsrdss-lp*d*1[s_q]s_>_lkly*sk2+lfx]Sf1lfxLsLkLyLpLfs_s_s_s_]sL
eush77
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