conversion of code swift 2.3 to swift 3

Question

let subString = self[Range(start: start++, end: endIndex)]
if subString.hasPrefix(other){
    return true
}

i have this code in swift 2.3, i used this code as an extension for string value, xcode converted it as follow

let subString = self[((start++) ..< endIndex)]

and start giving me error

Unary operator '++' cannot be applied to an operand of type '@lvalue String.Index' (aka '@lvalue String.CharacterView.Index')

i don't know now how exactly Xcode want me to write it?

Compare [How does String.Index work in Swift 3](http://stackoverflow.com/q/39676939/2976878) – you want to do `index(after: start)` (this won't mutate `start`, but you can easily do that by assigning to it on a seperate line). — Hamish, Apr 13 '17 at 10:38
that is what i am doing! i am just saying if i have talk about the same question and i can't comment! then what to do? — Gurjot Kalsi, Apr 13 '17 at 11:12

score 2 · Accepted Answer · answered Apr 13 '17 at 10:37

2

In Swift 3 you cannot increment String.Index directly by an Int.

I don't know exactly how start is defined but you could replace start++ with

self.index(start, offsetBy: 1)

answered Apr 13 '17 at 10:37

vadian

@GurjotKalsi Make sure you accept vadian's answer if it worked for you. – Adrian Apr 13 '17 at 11:31
yes i tried it said wait for few minutes! so i am just waiting – Gurjot Kalsi Apr 13 '17 at 11:35

1 Answers1