Adding seconds to time integer

Asked Apr 13 '17 at 23:14

Active Apr 13 '17 at 23:14

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I have day's time in integer formats like 152947 for (15 hour,29 min and 47 seconds), if I add seconds to that then I have to get integer in same format. eg

152947 + 40 => 153027

I do not want to use any time function, I know can do things like

int add2time(int timenum, int secs_to_add){
  int hour = timenum/10000;
  int minute = (timenum/100)%100;
  int second = (timenum%100);
  secs = hour * 3600 + minute * 60 + second;
  secs += secs_to_add;
  return (secs / 3600)*10000+((secs % 3600)/60)*100 + (secs % 60);
}

but as usual, I am looking for some faster ways to directly manipulate integer.

The problem is similar to below What is the standard way to add N seconds to datetime.time in Python?

edited May 23 '17 at 11:54

Community

asked Apr 13 '17 at 23:14

duckduckgo

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You can just add directly to the integer. Is the integer in ms? Then just multiply secs_to_add by 60, then add. – Evan Carslake Apr 13 '17 at 23:20
if you add then second part of integer can exceed 60 – duckduckgo Apr 13 '17 at 23:22
you can take it apart after you add the seconds, and it will not exceed 60. – Evan Carslake Apr 13 '17 at 23:23

Adding seconds to time integer

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