Can someone fake a $_SESSION variable? is it safe to just store a few variables using $_SESSION to determine if the user is logged in AND which user id he/she has? Could someone try to impersonate someone else through hacking session IDs?
I am retrieving a hashed password from the db and then I store a session to determine if user is logged in:
// Check username or email
$data = mysql_query("SELECT * FROM Users WHERE Username = '$username' OR Email = '$username'");
$num_rows = mysql_num_rows($data);
if($num_rows <= 0){ // Does username exist??
// ERROR MESSAGES
echo '<div class="error_messages";>';
echo 'Login combination is incorrect.';
echo '</div>';
}else{ // It exists, now checks password
while($row = mysql_fetch_array( $data )) {
$username_id = $row['id'];
$existingHashFromDb = $row['Password']; // Hash from db
$first_name = $row['FirstName'];
}
$isPasswordCorrect = password_verify($password, $existingHashFromDb);
if ( $isPasswordCorrect){ // Password is correct, user has logged in successfully!!
// Create a session saying that we are logged in
// And another session to store user's id
$_SESSION['loggedIn'] = true;
$_SESSION['userId'] = $username_id;
echo '<div class="success_messages";>';
echo 'Welcome back, ' . $first_name . '!';
echo '</div>';
}else{
echo '<div class="error_messages";>';
echo 'Login combination is incorrect.';
echo '</div>';
}
Then I would simply check who is logged in by using this function:
//checks if the user is logged in with the cookie on the browser, it returns 1 if logged, otherwise returns 0
function checkslogged()
{
if (isset($_SESSION['loggedin']) && $_SESSION['loggedin'] == true) {
return 1;
}else return 0;
}
Is this the best approach?