Deserialize json to anonymous C# object

Asked Apr 16 '17 at 12:36

Active Apr 16 '17 at 12:42

Viewed 3,178 times

I need to deserialize custom JSON to anonymous C# object.

My sample JSON (can be any, even with nested properties as objects):

var json = "{ 'Surname': 'Wick'}";

And I want to be deserialized as:

var jsonResult = new { Surname = "Wick" };

But I end up with something like this:

edited Apr 16 '17 at 12:38

m0nhawk

asked Apr 16 '17 at 12:36

mardok

1

See [this](http://stackoverflow.com/a/32187603/6400526) for Newtonsoft Json – Gilad Green Apr 16 '17 at 12:44
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The generic type you pass should be `dynamic` and not `object` – Gilad Green Apr 16 '17 at 12:54
@GiladGreen If use *dynamic* it ends up the same like I use *object* – mardok Apr 16 '17 at 13:08
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test the two but do `jsonResult.Surname` in the watch – Gilad Green Apr 16 '17 at 13:09
@GiladGreen http://imgur.com/a/Bjxqu – mardok Apr 16 '17 at 13:12
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I know :) that is why access the property `jsonResult.Surname` - with the object you'll get an exception, with dynamic you'll get the value. In both cases you get a dynamic object but in the `object` case it is cased to object... Also you can have a look under the `Dynamic View` line:) – Gilad Green Apr 16 '17 at 13:14
@GiladGreen *Json.Decode* gives better result, why JsonCoverter can't do the same? – mardok Apr 16 '17 at 13:16
1

then use `Json.Decode`... different frameworks, each with its own implementation – Gilad Green Apr 16 '17 at 13:17
1

@GiladGreen Thanks anyway :) – mardok Apr 16 '17 at 13:23
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You are welcome :) hope it helped – Gilad Green Apr 16 '17 at 13:23
In Json.Net, use [`JsonConvert.DeserializeAnonymousType()`](http://www.newtonsoft.com/json/help/html/M_Newtonsoft_Json_JsonConvert_DeserializeAnonymousType__1.htm) and give it an example of the anonymous type you want to deserialize into. – Brian Rogers Apr 16 '17 at 15:10

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