Take character from a specific position to last (swift 3)

Question

I have some string like "Md. Monir-Uz-Zaman Monir", "Md. Monir-Uz-Zaman Monir01", "Md. Monir-Uz-Zaman Monir876" .... Now I want to take a substring from 20th position character to last. Actually I want output like "Monir","Monir01", "Monir876"... The full string is not fixed but 1st 19 character is fixed.

I have done it in swift 2. But what would be answer for swift 3.

let nameString = str.substringWithRange(Range<String.Index>(start: str.startIndex.advancedBy(19), end: str.endIndex.advancedBy(0)))

Possible duplicate of [How does String substring work in Swift 3](http://stackoverflow.com/questions/39677330/how-does-string-substring-work-in-swift-3) — karthikeyan, Apr 17 '17 at 06:18
Possible duplicate of [How do you use String.substringWithRange? (or, how do Ranges work in Swift?)](http://stackoverflow.com/questions/24044851/how-do-you-use-string-substringwithrange-or-how-do-ranges-work-in-swift) — nayem, Apr 17 '17 at 06:30

score 2 · Accepted Answer · answered Apr 17 '17 at 06:24

Use map(_:) with array and then simply use substring(from:) with shorthand argument.

let strArray = ["Md. Monir-Uz-Zaman Monir", "Md. Monir-Uz-Zaman Monir01", "Md. Monir-Uz-Zaman Monir876"]
let nameArray = strArray.map { $0.substring(from: $0.index($0.startIndex, offsetBy: 19)) }
print(nameArray) //["Monir", "Monir01", "Monir876"]

score 1 · Answer 2 · answered Apr 17 '17 at 06:21

1

Convert string to array and get last object. Try below code

  let string : String = "Md. Monir-Uz-Zaman Monir"
  let fullNameArr = string.characters.split{$0 == " "}.map(String.init)
  print(fullNameArr[fullNameArr.count-1])

answered Apr 17 '17 at 06:21

kb920

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score 1 · Answer 3 · answered Apr 17 '17 at 06:31

1

// swift 3
let input = "Md. Monir-Uz-Zaman Monir"
let start = input.index(input.startIndex, offsetBy: 19)
let required = input[start..<input.endIndex] // "Monir

answered Apr 17 '17 at 06:31

Benzi

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Take character from a specific position to last (swift 3)

3 Answers3