Python: Only return integers

Question

I want to find the prime factors for 13195.

for num in range(1,13196):
    x = 13195/num

I want x to only store integers. I've tried is.integer and but keep getting syntax errors.

Duplicate of [this question](http://stackoverflow.com/questions/6800193/what-is-the-most-efficient-way-of-finding-all-the-factors-of-a-number-in-python). — Massimiliano Kraus, Apr 17 '17 at 17:20

score 4 · Answer 1 · answered Apr 17 '17 at 17:10

4

You could use the modulo operator to check if a number is divided evenly, and only set x equal to it then. E.g.:

for num in range(1,13196):
    if 13195 % num == 0:
        x = int(13195/num)
        print(x)

which gives:

answered Apr 17 '17 at 17:10

Kewl

4

No need for the `int` call if you use `//`. – DSM Apr 17 '17 at 17:17
1

You could also use `divmod(13195, num)` to get both the quotient and remainder as a tuple. https://docs.python.org/3/library/functions.html#divmod – gen_Eric Apr 17 '17 at 17:19

score 3 · Answer 2 · answered Apr 17 '17 at 17:15

I've tried is.integer and but keep getting syntax errors.

The method for checking if a float is an integer is called is_integer() not is.integer(), so alternatively, you can do this:

for num in range(1,13196):
    x = 13195/num 
    if x.is_integer():
        print(num)

Or by adding the brackets:

for num in range(1,13196):
    if (13195/num).is_integer():
        print(num)

2 Answers2