Call a GSM Service #123*

Question

I want to call a GSM-Servicenumber of my provider, but the iPhone won't give a reaction. When I try the same with a regular number it works.

[[UIApplication sharedApplication]
                openURL:[NSURL URLWithString:@"tel:#123*1*4#"]
];

Have anyone an idea to get the Phone dial the GSM-Code?

See this question: http://stackoverflow.com/questions/1478402/how-to-send-ussd-request-through-programming-on-iphone-os - it seems your only option is calling private CTCallDialWithID function from CoreTelephony framework — Vladimir, Dec 03 '10 at 14:37
@Vladimir thanks for updating ,But is it legal or illegal use coreTelephone and CTCallDialWithID ?? is it private or public ?? can it casing apple rejection for my app?? — Adel, Mar 30 '12 at 11:55
@cocos2dman, it is private method and you can't use it in application intended to be posted on Appstore — Vladimir, Mar 30 '12 at 11:59

score 3 · Accepted Answer · edited Feb 12 '14 at 09:25

it is not possible to use gsm-codes with public methods

See Apples Documentation about Phone Links:

To prevent users from maliciously redirecting phone calls or changing the behavior of a phone or account, the Phone app supports most, but not all, of the special characters in the tel scheme. Specifically, if a URL contains the * or # characters, the Phone app does not attempt to dial the corresponding phone number.

score 0 · Answer 2 · answered Jun 18 '18 at 12:26

0

Replace * with %2A and # with %23.

Your example would be:

[NSURL URLWithString:@"tel:%23123%2A1%2A4%23"]

answered Jun 18 '18 at 12:26

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Call a GSM Service #123*

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