facing issue in strtotime()

Question

I am facing an issue in echo date() with some formats like:

if i use the format d/m/Y like: '18/04/2017' then date() does not recognize this because the format contain /

<?php
  echo date("d-m-Y",strtotime('16/04/2017'));
?>

it will output: 01-01-1970

But when i use the format m/d/Y like: '04/18/2017' then date() it recognized

<?php
  echo date("d-m-Y",strtotime('04/16/2017'));
?>

it will output: 16-04-2017

I am not getting these different behaviour of date(), can anybody help me please

see this:: http://stackoverflow.com/questions/33825869/date-format-differences-between-d-m-y-and-d-m-y — Sudhir Bastakoti, Apr 18 '17 at 04:47
Use strtotime(str_replace('/','-','04/16/2017')); . http://php.net/manual/en/function.strtotime.php#100144 — blokeish, Apr 18 '17 at 04:51
Sorry about that. The link after explains that, which is same as what Mayank P posted below. — blokeish, Apr 18 '17 at 04:58

Mayank Pandeyz · Answer 1 · 2017-04-18T04:50:00.060

2

Forward slash (/) signifies American M/D/Y formatting, a dash (-) signifies European D-M-Y and a period (.) signifies ISO Y.M.D.

So if your date is like 04/16/2017, change the / to - and then use date() function on it to convert it to any format.

Reference

Working Code

edited Apr 18 '17 at 04:50

answered Apr 18 '17 at 04:45

Mayank Pandeyz

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Good to always give reference to your answer. http://php.net/manual/en/function.strtotime.php#100144. Use strtotime(str_replace('/','-','04/16/2017')) – blokeish Apr 18 '17 at 04:49
@Mayank Pandeyz thank you very much :) – lazyCoder Apr 18 '17 at 05:05

score 1 · Accepted Answer · edited Jun 20 '20 at 09:12

1

You can use date_create_from_format to convert your date to any format you want. The problem with your code was that strtotime does not support this format.

Learn about strtotime formats

If you using dd/mm/yyyy then it will not work because does not comes under support format of strtotime. For using

Supported formats: (for dd mm yyyy)

dd [.\t-] mm [.-] YY

Example: 16-04-2017

Example: 16.04.2017

Example: 16\t04t\2017

<?php
ini_set('display_errors', 1);
$date=date_create_from_format("d/m/Y","16/04/2017");
echo $date->format("d-m-Y");

edited Jun 20 '20 at 09:12

Community

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answered Apr 18 '17 at 04:49

Sahil Gulati

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yes it can be but what about my case – lazyCoder Apr 18 '17 at 04:51
thanks to share the strtotime formats – lazyCoder Apr 18 '17 at 05:02
@BunkerBoy Welcome .... :) – Sahil Gulati Apr 18 '17 at 05:03

score 0 · Answer 3 · answered Apr 18 '17 at 08:22

0

Another way is replace / with - of given date

$date = '16/04/2017';
$date = str_replace("/", "-", $date);
echo date("d-m-Y",strtotime($date));

answered Apr 18 '17 at 08:22

Hardeep Singh

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thanks i know but i got my answer – lazyCoder Apr 18 '17 at 09:20

facing issue in strtotime()

3 Answers3