JavaScript: Display positive numbers with the plus sign

Question

How would I display positive number such as 3 as +3 and negative numbers such -5 as -5? So, as follows:

1, 2, 3 goes into +1, +2, +3

but if those are

-1, -2, -3 then goes into -1, -2, -3

Answer 1

You can use a simple expression like this:

(n<0?"":"+") + n

The conditional expression results in a plus sign if the number is positive, and an empty string if the number is negative.

You haven't specified how to handle zero, so I assumed that it would be displayed as +0. If you want to display it as just 0, use the <= operator instead:

(n<=0?"":"+") + n

Answer 2

// Forces signing on a number, returned as a string
function getNumber(theNumber)
{
    if(theNumber > 0){
        return "+" + theNumber;
    }else{
        return theNumber.toString();
    }
}

This will do it for you.

Answer 3

A modern solution would be to use Intl.NumberFormat

const myNumber = 5;

new Intl.NumberFormat("en-US", {
    signDisplay: "exceptZero"
}).format(myNumber);

depending on what myNumber is it will display positive or negative sign, except when it's a 0.

Answer 4

printableNumber = function(n) { return (n > 0) ? "+" + n : n; };

Answer 5

write a js function to do it for you?

something like

var presentInteger = function(toPresent) {
    if (toPresent > 0) return "+" + toPresent;
    else return "" + toPresent;
}

you could also use the conditional operator:

var stringed = (toPresent > 0) ? "+" + toPresent : "" + toPresent;

Thanx to the comments for pointing out that "-" + toPresent would put a double -- on the string....

Answer 6

function format(n) {
    return (n>0?'+':'') + n;
}

Answer 7

['','+'][+(num > 0)] + num

or

['','+'][Number(num > 0)] + num

It is a shorter form than the ternary operator, based on casting boolean to the number 0 or 1 and using it as an index of an array with prefixes, for a number greater than 0 the prefix '+' is used

Answer 8

something along the lines of:

if (num > 0)
{
   numa = "+" + num;
}
else
{
   numa = num.toString();
}

and then print the string numa.

Answer 9

The solution with the ternary operator seems just fine, but for the fun of it, here is another one:

('+'+x).replace("+-", "-");

Answer 10

Modern syntax solution.

It also includes a space between sign and number:

function getNumberWithSign(input) {
  if (input === 0) {
    return "0"
  }

  const sign = input < 0 ? '-' : '+';

  return `${sign} ${Math.abs(input)}`;
}