How to explain the C code: char *s = "hello " "world";

Question

I tried the following C code by accident:

char *str = "hello " "world";

It's right, but I can't understand. How to explain this instrument?

What have you found out yourself? What does your C book say? Online tutorials? Your compiler? Anything? And how is that related to compiler construction? (and it is not gcc specific). — too honest for this site, Apr 18 '17 at 11:44
Adjacent string literals get concatenated. You could've looked it up. — DeiDei, Apr 18 '17 at 11:44

score 0 · Answer 1 · answered Apr 18 '17 at 12:02

According to the C Standard (5.1.1.2 Translation phases)

Adjacent string literal tokens are concatenated.

So after this translation phase this code snippet

char *str = "hello " "world";

is adjusted to

char *str = "hello world";

As result the pointer str points to the first character of the string literal "hello world".

score 0 · Answer 2 · answered Apr 18 '17 at 12:05

0

C standard says these literals are to be concatenated.

answered Apr 18 '17 at 12:05

Jeroen3

2 Answers2