Python: space in multiple-line format output

Question

Trying to re-factor codes by pep8.

Codes:

    print """Exception when sending email to: {0},
        from: {1}, subject: {2}, e: {3}""".format(to, fr, subject, e)

Output:

Exception when sending email to: to,
                from: fr, subject: subject, e: Invalid URL 'http//127.0.0.1:8000/'

How to remove the space before from in above output? Thanks

UPDATE

The following codes working fine. Should I delete this post?

 34             print ($
 35                 "Exception when sending email to: {0},"$
 36                 "from: {1}, subject: {2}, e: {3}").format(to, fr, subject, e)$

String literals don't need to be indented in the middle. – Ignacio Vazquez-Abrams Apr 18 '17 at 20:17 — Ignacio Vazquez-Abrams, Apr 18 '17 at 20:17

dot.Py · Answer 1 · 2017-04-18T20:24:08.230

0

Since you're using """, you should search for the term "triple-quotes" at this link.

Change:

print """Exception when sending email to: {0},
        from: {1}, subject: {2}, e: {3}""".format(to, fr, subject, e)

To:

print """Exception when sending email to: {0}, from: {1}, subject: {2}, e: {3}""".format(to, fr, subject, e)

Edit:

If you need to keep your lines short, you can also use \ to continue the multi-line statement:

Code:

print("""Exception when sending email \
to: {0}, \
from: {1}, \
subject: {2}, \
e: {3}""".format('to', 'fr', 'subject', 'e'))

Output:

Exception when sending email to: to, from: fr, subject: subject, e: e

edited Apr 18 '17 at 20:24

answered Apr 18 '17 at 20:17

dot.Py

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I need to keep each line containing less than 79 chars. – BAE Apr 18 '17 at 20:18
Updated my answer... take a look. – dot.Py Apr 18 '17 at 20:28

Python: space in multiple-line format output

1 Answers1