Regex with find command in bash

Question

I have been trying to use regex with find command in bash. Following are my codes:

find . -regextype posix-extended -regex 'AB[0-9]{1}_all_chr\.gz'

However, above code did not match to desired file with id such as "AB1_all_chr.gz" and "AB2_all_chr.gz". can someone help me out with this piece of code?

Needs `.*` at the start, you need the entire path to be a match. Also `[0-9]{1}` is redundant `[0-9]` already does a single char. — 123, Apr 18 '17 at 22:51
See [How to use regex with find command?](http://stackoverflow.com/questions/6844785/how-to-use-regex-with-find-command) — Wiktor Stribiżew, Apr 18 '17 at 22:53

score 0 · Answer 1 · answered Apr 18 '17 at 23:22

0

So, to provide an actual answer:

find . -regextype posix-extended -regex '^.*AB[0-9]_all_chr\.gz$'

Match any text at the beginning followed by AB and then any one digit and then ending with _all_chr.gz

answered Apr 18 '17 at 23:22

John Weldon

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Regex with find command in bash

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