dfply.mutate does not work with pandas.to_datetime

Asked Apr 19 '17 at 10:57

Active May 29 '18 at 00:06

Viewed 283 times

I have a DataFrame for which

hub2['time'] = pd.to_datetime(hub2.timestamp)

works, but when I write

hub2 >> mutate(time=pd.to_datetime(X.timestamp))

with https://github.com/kieferk/dfply I get the error

Traceback (most recent call last): File "<input>", line 1, in <module> File "[...]/lib/python2.7/site-packages/pandas/util/decorators.py", line 91, in wrapper return func(*args, **kwargs) File "[...]/lib/python2.7/site-packages/pandas/tseries/tools.py", line 419, in to_datetime elif isinstance(arg, ABCSeries): File "[...]/lib/python2.7/site-packages/pandas/types/generic.py", line 9, in _check return getattr(inst, attr, '_typ') in comp TypeError: __nonzero__ should return bool or int, returned Call

Why is that?

edited May 29 '18 at 00:06

www

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asked Apr 19 '17 at 10:57

Make42

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Yes, I think it is bug. https://github.com/kieferk/dfply/issues/27 – jezrael Apr 19 '17 at 11:20
@jezrael: I think so too, but I added the issue ;-). Then I thought, maybe it is not a bug and I better ask SO. – Make42 Apr 19 '17 at 11:22
One thing, it is not typo only? And also try add `[]` - `hub2 >> mutate(time=pd.to_datetime(hub2['timestamp']))` – jezrael Apr 19 '17 at 11:24
@jezrael: The `X.` is on purpose. If you look into dfply's documentation you will see that this is referring to the input dataframe. – Make42 Apr 19 '17 at 11:45
Ok, so good luck! – jezrael Apr 19 '17 at 11:46

dfply.mutate does not work with pandas.to_datetime

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