Insert data in bash prompt with script

Question

I created a bash script that perform some operations inside a while loop. In one command, the console asks for an input and I have no idea how to provide this input in order to continue with my script.

while read line;
do
    string_array=($line)
    username=${string_array[0]}
    password=${string_array[1]}
    kinit $username
        ===> here I need to enter the $password and press "ENTER" to continue

done <myfile

Any suggestion?

Inian · Accepted Answer · 2017-04-19T13:45:32.720

1

Change your main while-loop to read from a different file descriptor than stdin and use read to read from stdin and use -s to suppress text from showing up in console.

while read -u 3 line; do
    # Your rest of the code 
    read -s -p "Enter password: " password
done 3<myfile

edited Apr 19 '17 at 13:45

answered Apr 19 '17 at 13:30

Inian

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So, after the command "kinit $username", when I need to enter password, I use the command => read -s -p "Enter password: " password ??? – user3472065 Apr 19 '17 at 13:44
does not work :( the console is still stuck at "Enter password for user...." – user3472065 Apr 19 '17 at 13:46
@user3472065: You are either 1) not using the code as I suggested 2) or you have not posted the complete script. I did not have a string `Enter password for user`, do you have other `read` commands in your script? – Inian Apr 19 '17 at 13:47
I solved the issue doing that: echo $password | kinit $username – user3472065 Apr 19 '17 at 13:52
Thanks anyway for the support!!! – user3472065 Apr 19 '17 at 13:52

Insert data in bash prompt with script

1 Answers1