How to echo json object properties in php?

Question

JSON data

"orders":[  
     "billing_details":{  
        "company":"Test Company",
        "firstname":"Munadil",
        "postcode":"5000",
        "street":"Dhaka, Bangladesh",
        "email":"munadil98@gmail.com",
        "lastname":"Fahad",
        "ph_number":"880191111111",
        "city":"Dhaka",
        "state":"Mirpur",
        "country_code":"BN",
        "user_id":16003511,
        "salutation":null
     }]

In PHP

$json_output = json_decode($response);
foreach ( $json_output->orders as $orders ){
foreach ($orders->billing_details as $billing_details) {echo "<b>Name:</b><br>".$billing_details->firstname." ".$billing_details->lastname."<br>";}
}

But I am getting below error message,

Notice: Trying to get property of non-object in ....

How can I echo data inside "billing_details" object under array "orders" ?

`billing_details` is a key inside an array. Try `"orders":[{...}]` — mike.k, Apr 20 '17 at 20:07
@mike.k Please mention exact syntax to echo values inside billing_details — Munadil Fahad, Apr 20 '17 at 20:09
@MunadilFahad first please correct your json, bcoz the one you have shown above is invalid! — Iceman, Apr 20 '17 at 20:11
since this question has been marked as a duplicate here is a workaround `$json = json_decode(rtrim(substr($response, strpos($response, '{')), ']'));` — Junius L, Apr 20 '17 at 20:33
@victor, please check my revised post above, $orders was defined in parent foreach loop — Munadil Fahad, Apr 21 '17 at 16:26

Omi · Answer 1 · 2017-04-20T20:28:17.413

2

Try this:

$json_output = json_decode($response);

foreach ($json_output['orders'] as $billing_details) {
echo "<b>Name:</b><br>$billing_details['firstname'] $billing_details['lastname']<br>";}

edited Apr 20 '17 at 20:28

answered Apr 20 '17 at 20:20

Omi

3,954
5
21
41

tell us this will work. – Junius L Apr 20 '17 at 20:24
@julekgwa Thanks i have updated answer – Omi Apr 20 '17 at 20:30
this won't work. – Junius L Apr 20 '17 at 20:34
i dont understand why? – Omi Apr 20 '17 at 20:34
have you tested it? – Junius L Apr 20 '17 at 20:35
yes i have .it works – Omi Apr 20 '17 at 20:36
I wonder how you have tested, as I'm getting tons of errors using your code. – Junius L Apr 20 '17 at 20:39
i think there is some mistake in json – Omi Apr 20 '17 at 20:46

score 1 · Answer 2 · answered Apr 20 '17 at 20:17

1

Try this

$json_output = json_decode($response['orders']);

echo $json_output;

answered Apr 20 '17 at 20:17

Muhammad Ahsan

297
2
15

How do you echo an array? Btw, `$response` is a string at this point so `$response['orders']` will fail. – M. Eriksson Apr 20 '17 at 20:20
Problem solved. Actually, I found that some "orders" array don't have "billing_details" object. This was the reason of returning error. For the "orders" array which have "billing_details" object found ok. So, I get rid of showing error message by if else condition. Thank you all for your support. – Munadil Fahad May 01 '17 at 10:42
Your problem solved.Thats great!! – Muhammad Ahsan May 01 '17 at 13:55

How to echo json object properties in php?

JSON data

In PHP

2 Answers2