Error in reading video using opencv in Python

Question

Not able to read a video file using openCV in Python3.

Code:

import numpy as np
import cv2

cap = cv2.VideoCapture('C:\Users\u266772\Desktop\Video\video2.mp4')

while(cap.isOpened()):
    ret, frame = cap.read()

    gray = cv2.cvtColor(frame, cv2.COLOR_BGR2GRAY)

    cv2.imshow('frame',gray)
    if cv2.waitKey(1) & 0xFF == ord('q'):
        break

cap.release()
cv2.destroyAllWindows()

Error:

File "", line 4 cap = cv2.VideoCapture('C:\Users\u266772\Desktop\Video\video2.mp4') ^ SyntaxError: (unicode error) 'unicodeescape' codec can't decode bytes in position 2-3: truncated \UXXXXXXXX escape

Possible duplicate of [Why do I get a SyntaxError for a Unicode escape in my file path?](http://stackoverflow.com/questions/18084554/why-do-i-get-a-syntaxerror-for-a-unicode-escape-in-my-file-path) — Ahsanul Haque, Apr 23 '17 at 05:03
Thanks. The below changes in the code worked: cap = cv2.VideoCapture("C:/Users/u266772/Desktop/Video/video2.mp4") — M Kumar, Apr 23 '17 at 05:29

score -1 · Answer 1 · edited Apr 04 '21 at 06:23

-1

Just change the way you write file path

import numpy as np
import cv2

cap = cv2.VideoCapture('C:\\\Users\\\u266772\\\Desktop\\\Video\\\video2.mp4')

while(cap.isOpened()):
    ret, frame = cap.read()

    gray = cv2.cvtColor(frame, cv2.COLOR_BGR2GRAY)

    cv2.imshow('frame',gray)
    if cv2.waitKey(1) & 0xFF == ord('q'):
        break

cap.release()
cv2.destroyAllWindows()

edited Apr 04 '21 at 06:23

tomerpacific

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answered Apr 03 '21 at 17:40

apoorva Srivastava

1

Error in reading video using opencv in Python

1 Answers1