Java compiler shows error that “integer is too large”

Question

when I add integer number it's show me "integer too large" even if I make it double howto solve this

public class Three {
public static void main(String[] args) {
    int i = 05955555;
}

Remove leading 0. It sets literal in octal base so only 0-7 digits are accepted. — Pshemo, Apr 23 '17 at 17:18
Also see: http://stackoverflow.com/questions/7218760/why-is-08-not-a-valid-integer-literal-in-java — GhostCat, Apr 23 '17 at 17:19

score 1 · Accepted Answer · answered Apr 23 '17 at 17:20

1

Try this instead:

int i = 5955555;

In Java, an integer number starting with 0 is interpreted as being in octal base - and in that base, you can't have the digit 9.

answered Apr 23 '17 at 17:20

Óscar López

1 Answers1