nodejs fork child process without terminal (hidden)

Asked Apr 23 '17 at 18:17

Active Apr 24 '17 at 00:21

Viewed 1,617 times

Introduction: When invoking a child process with the fork() method, the child's output is connected to the master terminal and you can see the logs there. The specific command I use to fork a process is fork(myScript.js, [aFewArguments]). No options are specified.

Specific situation: When I start the master node process without a terminal window using the command pm2 start script.js and then try to invoke a child process, a new terminal opens up for each forked process and thus pollutes the screen of the machine I am using.

I cannot find any information how to hide/remove the child process terminal from appearing. Is there any way to hide/stop the child process terminals from opening?

edited Apr 24 '17 at 00:21

Omri Luzon

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asked Apr 23 '17 at 18:17

Ivan Parushev

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Make sure you read [this](http://stackoverflow.com/questions/17861362/node-js-child-process-difference-between-spawn-fork) – Omri Luzon Apr 23 '17 at 18:22
I dont see how this is connected to hiding the terminal – Ivan Parushev Apr 23 '17 at 19:42
Perhaps using `spawn()` and [`options.detached`](https://nodejs.org/api/child_process.html#child_process_options_detached) fixes it? – robertklep Apr 23 '17 at 19:54

nodejs fork child process without terminal (hidden)

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