php variable assignment to display html & php variable

Question

I'm having a php noob moment, im looking for a smaller more compact solution to concatenate the "$content" variable which is being echoed as the main content in an external "layout.php" file.

<?php

require_once("Controller/comment_control.php");
$comment = new COMMENT();

$title = "Customer Reviews";
$content = '<div class="comment_box">'   ;
$content .=  $comment->getComments(); 
$content .=  '</div>';

any help condensing this ugly mess is appreciated.

If you're looking for suggestions on coding style, the correct place to post is CodeReview.stackexchange.com. SO is for help fixing problems in code. — Barmar, Apr 24 '17 at 08:02

score 0 · Answer 1 · answered Apr 24 '17 at 07:58

0

figured it out, encompassing the php call in parenthesis got the end result i wanted

$content = '<div class="comment_box">'  .  ($comment->getComments() ) .  '</div>';

answered Apr 24 '17 at 07:58

rsahs

3
4

Your original code should work exactly the same. If you're seeing the source code, it's a different problem. – Barmar Apr 24 '17 at 07:59

score 0 · Answer 2 · answered Apr 24 '17 at 07:59

0

Use sprintf()

SPRINTF

Example:

$content = sprintf('<div class="comment_box">%s</div>', $comment->getComments());

answered Apr 24 '17 at 07:59

Niek van der Maaden

492
3
16

Why would this work any differently from his original code? – Barmar Apr 24 '17 at 07:59
Because he asked: im looking for a smaller more compact solution to concatenate the "$content" variable – Niek van der Maaden Apr 24 '17 at 08:00
I thought his problem was that he's seeing the source code on the web page. – Barmar Apr 24 '17 at 08:00
You're right there's 2 questions in the question of OP. – Niek van der Maaden Apr 24 '17 at 08:01
edited the op to clean up confusion. it was not intended to be two questions. Thanks for your replies, I can't believe I forgot about sprintf(); – rsahs Apr 24 '17 at 08:50

php variable assignment to display html & php variable

2 Answers2