Function to find vowels in a word?

Question

I have a problem where I have to use a function to output the vowels in a word and output how many vowels there are. I just took a computing course at the local college and am new to this whole thing and its going over my head a bit.

I tried but this is what i got when I ran it:

TypeError: vowel() takes 0 positional arguements but 1 was given

My code:

def vowel ():
  array = []
  counter = 0
  for i in word:
    if i in ("a","e","i","o","u"):
      counter+=1
      array.append(i)
  return (array, counter)

word = input("Enter your word")
function = vowel(word)
print(function)

Look, your function definition doesn't accept any argument, while inside `vowel(word)` you do send it an argument. — elena, Apr 25 '17 at 17:26
just change `def vowel ():` to `def vowel (word):`, your code works fine. — chickity china chinese chicken, Apr 25 '17 at 17:27
Same problem as [Python - TypeError: create\_purple() takes 0 positional arguments but 2 were given](http://stackoverflow.com/questions/26144191/python-typeerror-create-purple-takes-0-positional-arguments-but-2-were-give) — Celeo, Apr 25 '17 at 17:27
http://anh.cs.luc.edu/python/hands-on/3.1/handsonHtml/functions.html — Celeo, Apr 25 '17 at 17:29

score 1 · Answer 1 · answered Apr 25 '17 at 17:34

1

Actually, the error is simple.

When you define the function Vowel, It doesn't recieve any argument.

It should look like this:

def vowel (word):

Hope i can help you :D

answered Apr 25 '17 at 17:34

Gerard Ramon

67
2
11

thank you so much you really helped me out :) – MasterBaggins2319 Apr 25 '17 at 17:48

score 1 · Answer 2 · answered Apr 25 '17 at 17:35

The number of arguments given in the function definition and function call should be same. In the function definition, you have written def vowel(): but while calling function = vowel(word) you are providing an argument to the function. Hence it throws an error. You can modify it as:

def vowel(word):
   array = []
   counter = 0
   for i in word:
     if i in ("a","e","i","o","u"):
       counter+=1
       array.append(i)
   return (array, counter)

word = input("Enter your word")
function = vowel(word)
print(function)

thanks so much it works now – MasterBaggins2319 Apr 25 '17 at 17:49 — MasterBaggins2319, Apr 25 '17 at 17:49

score 0 · Answer 3 · edited May 23 '17 at 12:26

0

In function definition, you forgot to provide word

def vowel (word):
  array = []
  counter = 0
  for i in word:
    if i in ("a","e","i","o","u"):
      counter+=1
      array.append(i)
  return (array, counter)


word = input("Enter your word")
function = vowel(word)
print(function)

To read more about Positional arguments see this post Positional argument v.s. keyword argument

edited May 23 '17 at 12:26

Community

1
1

answered Apr 25 '17 at 17:27

JkShaw

1,927
2
13
14

simple mistake :) I feel like an idiot now but thank you so much – MasterBaggins2319 Apr 25 '17 at 17:50

milouk · Answer 4 · 2017-04-25T17:45:29.517

0

The error is self explanatory. You declared the function vowel to be seeded with 0 arguments.

def vowel ():

and you called it seeding it with one argument:

 function = vowel(word)

what you should have done is:

def vowel (word):
    array = []
    counter = 0
    for i in word:
        if i in ("a","e","i","o","u"):
        counter+=1
        array.append(i)
    return (array, counter)

edited Apr 25 '17 at 17:45

answered Apr 25 '17 at 17:31

milouk

171
1
3
11

thanks the program works well now – MasterBaggins2319 Apr 25 '17 at 17:51

score 0 · Answer 5 · answered Apr 25 '17 at 17:34

0

You can use a function and then simple list comprehension:

def vowel(word):
   array = [i for i in word if i in ("a","e","i","o","u")]
   counter = len(array)
   return array, counter

word = input("Enter your word")
function = vowel(word)
print(function)

answered Apr 25 '17 at 17:34

Ajax1234

69,937
8
61
102

thank you lots the program works really well – MasterBaggins2319 Apr 25 '17 at 17:50

Function to find vowels in a word?

5 Answers5