Compare swapped two list of each value using linq in c#

Question

Here is my cases,

ListA "1", "2", "3"
ListB "2", "1", "3"

If ListA == ListB, => it should return true since ListA values are in ListB.

ListA "1", "2", "3"
ListB "1", "2", "3", "4"

=> it should return false since ListB of 4 is not in ListA.

Can anybody help on this?

What should happen if LISTA "1", "2", "3" and LISTB "2", "1", "3", "3"? Or are you worried about that case? — KSib, Apr 26 '17 at 15:44
I think you're right @Sinatr. The solution I came up with is already on there using sequenceequal and orderby. — KSib, Apr 26 '17 at 15:47
@KSib Actually it is invalid case since having duplicate values. Anyway it should return false since ListA and LisB length is not equal. — cgsabari, Apr 26 '17 at 15:51
Thanks for the clarification. I think your answer is in the link @Sinatr likely posted — KSib, Apr 26 '17 at 15:54

score 3 · Answer 1 · answered Apr 26 '17 at 15:41

3

You need to use Except and then Any

var result = !ListB.Except(ListA).Any();

answered Apr 26 '17 at 15:41

Nikhil Agrawal

This will work assuming no duplicate values ever show up in ListB. – KSib Apr 26 '17 at 15:43
@Ksib: Duplicate will also work fine. Say `ListB` has an extra 3, still result returns `true`. – Nikhil Agrawal Apr 26 '17 at 15:49
It wasn't a question for you, I was clarifying for cgsabari that this is fine if he doesn't mind duplicates. If he does mind duplicates then this won't work. Actually, it looks like this won't work for his requirements as he commented just now – KSib Apr 26 '17 at 15:52

score 2 · Answer 2 · answered Apr 26 '17 at 15:42

2

If lists contain only unique values you can use HashSet and SetEquals method

new HashSet(listA).SetEquals(new HashSet(listB));

answered Apr 26 '17 at 15:42

Valentin

2 Answers2