Password Patteren does not matched with the Matcher class

Question

My Password should be Like :

"Password should contain at least one uppercase letter, one lowercase letter, one digit and one special character with minimum eight character length"

The Pattern I have used is : ^(?=.*[a-z])(?=.*[A-Z])(?=.*\\d)(?=.*[$@$#!%*?&])[A-Za-z\\d$@$#!%*?&]{8,}

So, I have created a function as below in my Constant.java file :

public static Boolean passwordMatcher(TextInputLayout edtText,String string) {
    Pattern pattern = Pattern.compile("^(?=.*[a-z])(?=.*[A-Z])(?=.*\\\\d)(?=.*[$@$#!%*?&])[A-Za-z\\\\d$@$#!%*?&]{8,}");
    Matcher matcher = pattern.matcher(edtText.getEditText().getText().toString());
    boolean isMatched = matcher.matches();
    if (isMatched) {
        return true;
    }
    if (!isMatched) {
        edtText.setErrorEnabled(true);
        edtText.setError("" + string);
        edtText.setFocusable(true);
        return false;
    }
    return true;
}

and in my MainActivity.java file I have checked for validation as below :

if (!Constant.passwordMatcher(edtPassword, mContext.getResources().getString(R.string.error_activity_signup_password_invalid))) {
    return;
}

But, I am not getting success even if I have tried : 'Jaimin123#' as a my password. Always getting error set in my TextInputLayout.

What might be the issue ?

Thanks.

Take a look here http://stackoverflow.com/questions/23214434/regular-expression-in-android-for-password-field — IntelliJ Amiya, Apr 27 '17 at 06:20
Possible duplicate of [Password must be 8 characters including 1 uppercase letter, 1 special character, alphanumeric characters](http://stackoverflow.com/questions/9477906/password-must-be-8-characters-including-1-uppercase-letter-1-special-character) — Janak, Apr 27 '17 at 06:22
Possible duplicate of [Regular Expression In Android for Password Field](http://stackoverflow.com/questions/23214434/regular-expression-in-android-for-password-field) — Jitesh Prajapati, Apr 27 '17 at 06:23

Priyank Patel · Accepted Answer · 2017-04-27T06:55:50.250

3

Try using below regex for password match.

^(?=.*?[A-Z])(?=(.*[a-z]){1,})(?=(.*[\d]){1,})(?=(.*[\W]){1,})(?!.*\s).{8,}$

This regex will check for below rules:

At least one upper case letter
At least one lower case letter
At least one digit
At least one special character
Minimum 8 in length

edited Apr 27 '17 at 06:55

answered Apr 27 '17 at 06:34

Priyank Patel

12,244
8
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Aldrin Joe Mathew · Answer 2 · 2017-04-27T06:34:09.117

1

Try this

^(?=.*[a-z])(?=.*[A-Z])(?=.*[0-9])(?=.*[$@#!%*?&]).{8,}$

If you don't want white space in password include (?=\S+$) also

edited Apr 27 '17 at 06:34

answered Apr 27 '17 at 06:24

Aldrin Joe Mathew

472
1
4
13

java.util.regex.PatternSyntaxException: Syntax error in regexp pattern near index 50: ^(?=.*[a-z])(?=.*[A-Z])(?=.*\\d)(?=.*[$@$#!%*?&]){8,}$ – ZaptechDev Kumar Apr 27 '17 at 06:29

score 1 · Answer 3 · answered Apr 27 '17 at 06:49

Try this code:

public void checkPattern(String password) {     
    Pattern pattern = Pattern.compile("(?=.*\\d)(?=.*[A-Z])(?=.*[a-z])(?=.*\\W).{8,}");
    Matcher matcher = pattern.matcher(password);
    boolean isMatched = matcher.matches();
    System.out.println(isMatched);
}

score 0 · Answer 4 · answered Apr 27 '17 at 06:56

Try

public boolean matchesPattern(String password) {        
    Pattern pattern = Pattern.compile("^(?=.*?[A-Z])(?=(.*[a-z]){1,})(?=(.*[\d]){1,})(?=(.*[\W]){1,})(?!.*\s).{8,}$");
    Matcher matcher = pattern.matcher(password);
    return matcher.matches();
}

Password Patteren does not matched with the Matcher class

4 Answers4