Open file in the same directory

Asked Apr 27 '17 at 08:39

Active Apr 27 '17 at 08:39

Viewed 8,681 times

I've an __init__.py file in my Database package and I would want to read some information from a configuration file (config.json) in the same directory.

I've tried this code:

with open("config.json", 'r') as json_data:
    data = json.load(json_data)
print(data)

but i got this error:

FileNotFoundError: [Errno 2] No such file or directory: 'config.json'

Where is the mistake?

asked Apr 27 '17 at 08:39

Federico Cuozzo

2

`import os ; print(os.getcwd())` to see where your script is actually running from – DeepSpace Apr 27 '17 at 08:40
3

Working directory =/= directory where script is located – el.pescado - нет войне Apr 27 '17 at 08:42
Possible duplicate of [How to get full path of current file's directory in Python?](http://stackoverflow.com/questions/3430372/how-to-get-full-path-of-current-files-directory-in-python) – Jean-François Fabre Apr 27 '17 at 08:47
2

`with open(os.path.join(os.path.dirname(__file__),"config.json"), 'r') as json_data:` – Jean-François Fabre Apr 27 '17 at 08:47
Resolved. Thank you all. – Federico Cuozzo Apr 27 '17 at 08:50

Open file in the same directory

0 Answers0