Remove elements from a list that are contained in other list

Asked Apr 27 '17 at 18:46

Active Apr 27 '17 at 19:52

Viewed 69 times

I have two lists

users

[[[u'1-tpbvixq4-j1mjkfcl'], [u'1-oufnhv4b-j1tbyxvt']], 2, None]

constrained_users

[[[u'1-oufnhv4b-j1tbyxvt']], 1, None]

I'm trying to remove constrained_users from users, but I'm not being able to do it.

This is my code, trying to match them so far:

if any(users[0][0] in u for u in constrained_users[0]):
    print "true"
else:
    print "false"

But I'm always getting false.

How can I remove the constrained_users from users?

edited Apr 27 '17 at 19:52

Antimony

asked Apr 27 '17 at 18:46

Filipe Ferminiano

@Serge the issue is with list indexing on nested lists though. I think that's the barrier to implementation. – roganjosh Apr 27 '17 at 18:50
Swap the containment check: `any(u in users[0] for u in constrained_users[0])` – Moses Koledoye Apr 27 '17 at 18:52
`[user for user in users[0] if user not in constrained_users[0]]` will gen a list of users not in `constrained_users`. – TemporalWolf Apr 27 '17 at 18:54
Thanks! @ TemporalWolf – Filipe Ferminiano Apr 27 '17 at 19:48

0 Answers0