python - how to do list in list

Question

country=['Uruguay', 'Mexico', 'Uruguay', 'France', 'Mexico']

I have to count the occurrence of element in list. This is my output.

['Uruguay', 2, 'Mexico', 2, 'France', 1]

But how to do the list in list like below?

[['Uruguay', 2], ['Mexico', 2], ['France', 1]]

If the final order doesn't matter: `[[i, country.count(i)] for i in set(country)]` — Dimitris Fasarakis Hilliard, Apr 28 '17 at 10:22
just do `temp.append([i, count])` instead of doing `temp2.append(i); temp2.append(count)` in order to make your code work — JkShaw, Apr 28 '17 at 10:27

Rahul K P · Answer 1 · 2017-04-28T10:37:53.930

0

You can implement with list comprehension.

In [5]: print [[i,country.count(i)] for i in set(country)]
Out[5]: [['Mexico', 2], ['France', 1], ['Uruguay', 2]]

Also with collections.Counter,

from collections import Counter
result = map(list,Counter(country).items())

edited Apr 28 '17 at 10:37

answered Apr 28 '17 at 10:24

Rahul K P

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score 0 · Answer 2 · answered Apr 28 '17 at 10:24

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Take a look at collections.Counter and List Comprehensions

>>> country = ['Uruguay', 'Mexico', 'Uruguay', 'France', 'Mexico']
>>> [[i, j] for i, j in collections.Counter(country).items()]
[['Mexico', 2], ['France', 1], ['Uruguay', 2]]

answered Apr 28 '17 at 10:24

luoluo

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What's the point of that list comprehension? – Daniel Roseman Apr 28 '17 at 10:28
The OP want a list of list as his result. @DanielRoseman – luoluo Apr 28 '17 at 10:28
@DanielRoseman list of what? could show me please? the result should be a list of list? – luoluo Apr 28 '17 at 10:31
@vovaminiof that give your a list of tuple, not a list of list my friend. – luoluo Apr 28 '17 at 10:57
why would need exactly list? Anyhow, it can be also done like following: map(list, collections.Counter(country).items()) – vovaminiof Apr 28 '17 at 11:00
I am not a big fun of list myself. The OP said clearly he want a list of list. So I don't want to give an apple when a banana is needed. @vovaminiof – luoluo Apr 28 '17 at 11:01

python - how to do list in list

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