You don't need any new module to solve this problem. The JSON output is a string type and you can use a loop
and an if/elif/else
to solve it as in the example below:
import json
my_list = [1, 2, 3]
my_dict = {"key": "value", "boolean": True}
my_json = {"object": my_dict, "array": my_list}
json_dumps = json.dumps(my_json, indent=4)
str_to_write = ''
skip = 0
for char in json_dumps :
if (skip == 1) and ((char == '\n') or (char == ' ')) :
pass
elif (char == '[') :
skip = 1
str_to_write = str_to_write + char
elif (char == ']') :
skip = 0
str_to_write = str_to_write + char
else :
str_to_write = str_to_write + char
print(str_to_write)
Unfortunatly, it also strips the space character inside the lists. The output is:
{
"object": {
"key": "value",
"boolean": true
},
"array": [1,2,3]
}
Using regex
module, you can keep the spaces:
import regex as re
import json
my_list = [1, 2, 3]
my_dict = {"key": "value", "boolean": True}
my_json = {"object": my_dict, "array": my_list}
json_dumps = json.dumps(my_json, indent=4)
start = [m.start() for m in re.finditer('\[', json_dumps)]
end = [m.start() + 1 for m in re.finditer('\]', json_dumps)]
original = []
alterated = []
for s, e in zip(start, end) :
original.append(json_dumps[s:e])
alterated.append(json_dumps[s:e].replace('\n', '').replace(' ', '').replace(',', ', '))
for o, a in zip(original, alterated) :
json_dumps = json_dumps.replace(o, a)
print(json_dumps)
The output:
{
"object": {
"key": "value",
"boolean": true
},
"array": [1, 2, 3]
}