Check URL for given string

Question

I want to show/hide a div with a navbar inside of it. Whenever the URL has /profile in it i want it to show the navbar. At this moment I have this:

JS

app.controller('MainCtrl',['$scope', '$location', function($scope, $location) {
    $scope.isActive = function(viewLocation) {
        return viewLocation === $location.path();
    };
    $scope.$location = $location;
}]);

HTML

<div ng-show="isActive('/profile')" ng-controller="MainCtrl">

At this point it only shows the div when its :

www.randomwensite.com/profile

But when i go a page further its gone.

I want it showing whenever the whole URL contains /profile.

Like this: www.randomwebsite.com/profile/shop/edit

or: www.randomwebsite.com/profile/account

Any idea how I would be able to get that done?

Possible duplicate of [How to check if a string "StartsWith" another string?](http://stackoverflow.com/questions/646628/how-to-check-if-a-string-startswith-another-string) — Mistalis, May 02 '17 at 13:22

score 0 · Accepted Answer · answered May 02 '17 at 13:19

0

use indexOf to find a string in a string

app.controller('MainCtrl',['$scope', '$location', function($scope, $location) {
    $scope.isActive = function(viewLocation) {
        return   $location.path().indexOf(viewLocation);
    };
    $scope.$location = $location;
}]);

answered May 02 '17 at 13:19

Sachila Ranawaka

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When i tried `indexOf`it did not seem to work, when i changed that out for `includes` it does work. Thanks anyways! – Thomas van Strijland May 02 '17 at 13:27
sorry what do you mean by out for `includes` – Sachila Ranawaka May 02 '17 at 13:28
1

I swapped the .indexOf in this: `return $location.path().indexOf(viewLocation);` to .includes: `return $location.path().includes(viewLocation);` . – Thomas van Strijland May 02 '17 at 13:32

Check URL for given string

1 Answers1