I would like to use functools.partial
to set a certain argument to a constant and at the same time remove the argument altogether.
Let me explain it using a simple example.
from functools import partial
def f(a, b):
return a * b
g = partial(f, b=2)
However, this function g
still has the following calling signature:
g?
Signature: g(a, *, b=1)
Call signature: g(*args, **kwargs)
Type: partial
String form: functools.partial(<function f at 0x7ff7045289d8>, b=1)
File: /opt/conda/envs/dev/lib/python3.6/functools.py
Docstring:
partial(func, *args, **keywords) - new function with partial application
of the given arguments and keywords.
I could of course do this with a lambda function like:
def f(a, b):
return a * b
g = lambda a: f(a, b=2)
with the correct calling signature:
g?
Signature: g(a)
Docstring: <no docstring>
File: ~/Work/<ipython-input-7-fc5f3f492590>
Type: function
The downside of using lamdba
functions is that I would need to write down all the arguments again. In my simple example this doesn't matter, but look at this:
phase_func = lambda site1, site2, B_x, B_y, B_z, orbital, e, hbar: \
phase_func(site1, site2, B_x, B_y, B_z, orbital, e, hbar, xyz_offset=(0,0,0))
# or this
phase_func = partial(phase_func, xyz_offset=(0,0,0)
Why would I even want this?
Later in my code I use wrappers that can generate a new function by multiplying two other functions, like combine(function1, function2, operator.mul)
. This combine
function looks at all the arguments, therefore I need to remove the argument after setting it.