Get all bash subshells from command in php

Question

I need to detect if a command have sudo command in one of it's sub commands, so far I have this:

public function split_command($command) {
    // this regex is not perfect but work
    $separators = "/(?:\"[^\"\\\\]*(?:\\\\[\S\s][^\"\\\\]*)*\"|'[^'\\\\]*(?:\\\\[\S\s][^'\\\\]*)*')(*SKIP)(*F)|(\s+(?:&&|\|{1,2}|;)\s+)/";
    $flags = PREG_SPLIT_NO_EMPTY | PREG_SPLIT_DELIM_CAPTURE;
    return preg_split($separators, $command, null, $flags);
}
public function have_sudo($command) {
    $re = "!^(sudo|" . shell_exec("which sudo") . ")!";
    foreach ($this->split_command($command) as $part) {
        if (preg_match($re, trim($part))) {
            return true;
        }
    }
}

but if fail is command look like this: echo `sudo whoami`. How can I parse the command to get list of sub shells.

it should also work for commands like this:

$(some command; `other command (different command) $(some command)`)

it should return array:

["some command; `other command (different command) $(some command)`",
 "`other command (different command) $(some command)",
 "different command", "some command"]

so I can call have_sudo recursively on each element of the array the other option is to return most outer subshells from command.

[Regex cannot possibly be used for (arbitrary and correct) parsing](https://stackoverflow.com/q/1732348) (this applies to HTML as well as to programming languages). You'll need, well, a parser. — Siguza, May 03 '17 at 15:29

score 0 · Accepted Answer · answered May 03 '17 at 16:13

I've created a parser:

public function get_subshells($command) {
    $re = '/(\$\(|\(|\)|`)/';
    $parts = preg_split($re, $command, -1, PREG_SPLIT_DELIM_CAPTURE | PREG_SPLIT_NO_EMPTY);
    $subshells = array();
    $backtick = false;
    $stack = array();
    foreach ($parts as $part) {
        if (preg_match($re, $part)) {
            if ($part == "`") {
                $backtick = !$backtick;
            }
            if ($backtick || preg_match("/\(/", $part)) {
                $stack[] = array('tag' => $part, 'content' => '');
            } else {
                $last = array_pop($stack);
                $subshells[] = preg_replace('/^(\$\(|\(|`)/', '', $last['content']);
            }
        }
        if (count($stack) > 0) {
            foreach ($stack as &$subshell) {
                $subshell['content'] .= $part;
            }
        }

    }
    return array_reverse($subshells);
}

Get all bash subshells from command in php

1 Answers1