How to get values from JSONObject in Java?

Question

I am trying to parse a JsonArray and get its values but I am gettign error when I use

   jitem.getString("firstitem");

or

  jitem.getJSONObject("firstitem");

or

 jitem.get("firstitem");

Following is the code snippet.

  JSONArray arr_items = new JSONArray(str); 
        if(arr_items!=null && arr_items.size()>0){

            for(int i=0;i<arr_items.size();i++){
            JSONObject jitem = arr_items.getJSONObject(i);//works fine till here
             jitem.getString("firstitem"); //throws exception here
            }

This is the JSONArray that I am parsing

 [{"firstitem":"dgfd","secondtitem":"dfgfdgfdg","thirditem":"fdgfdgdf@sjhasjkdsha.com","fourthitem":"jkksdjklsfjskj"}]

what I am doing wrong? How to get these values by using keys?

Update:Note This array and its parameters are not null at all. They all have valid values.

which json library are you using? Since you have mixed methods of org.json and org.json.simple — Sachin Gupta, May 04 '17 at 11:28
@Henry I am getting different exceptions on all three. On 'getString' system is throwing null value though the values are present. On 'get' I think (not sure, as I deleted logs) it is saying soemthing about structure though structure is exactly what I mentioned in OP. — Just_another_developer, May 04 '17 at 11:38
http://stackoverflow.com/questions/2255220/how-to-parse-a-json-and-turn-its-values-into-an-array check this — gladiator, May 04 '17 at 11:47
@gladiator this is something different, link that you shared tells how to parse/convert JSONArray into JSONObject. I have already done it successfully, My problem is that I am unable to get value of individual item of JSONObject. — Just_another_developer, May 04 '17 at 11:50

score 0 · Answer 1 · answered May 04 '17 at 11:26

0

First check arr_items is not empty. Then, try surrounding your snippet with try/catch :

try {
       your snippet

      } catch (JSONException e) {
          e.printStackTrace();
      }

answered May 04 '17 at 11:26

RockDaFox

217
2
9

How does this solve the problem? It avoids an exception, but one still does not have the value. – Henry May 04 '17 at 11:44
In Android Studio if i don't surround with try/catch this type of snippet, the editor give an alert and i must surround it. So maybe, he can try – RockDaFox May 04 '17 at 12:03

score 0 · Answer 2 · answered May 04 '17 at 12:13

Check below

String json ="{'array':" + "[{'firstitem':'dgfd','secondtitem':'dfgfdgfdg','thirditem':'fdgfdgdf@sjhasjkdsha.com','fourthitem':'jkksdjklsfjskj'}]"+ "}";
     JSONObject myjson = new JSONObject(json);
    JSONArray the_json_array = myjson.getJSONArray("array");

    int size = the_json_array.length();
//  ArrayList<JSONObject> arrays = new ArrayList<JSONObject>();
    for (int i = 0; i < size; i++) {
        JSONObject another_json_object = the_json_array.getJSONObject(i);
    //  arrays.add(another_json_object);
        System.out.println(another_json_object.get("firstitem"));
    }

it require some array name so appended array name to it , if you want without it you have to add GSON.

How to get values from JSONObject in Java?

2 Answers2