Python - Rounding to two specific digits EXACTLY

Question

The number I have = 52.003

The number I want = 52.00

The number I get after rounding to 2 decimal places:

    round(52.003, 2)
    >>> 52.0

How do I keep the second digit without Python automatically rounding it?

http://stackoverflow.com/questions/8885663/how-to-format-a-floating-number-to-fixed-width-in-python — suvy, May 06 '17 at 02:56
Possible duplicate of [How to format a floating number to fixed width in Python](http://stackoverflow.com/questions/8885663/how-to-format-a-floating-number-to-fixed-width-in-python) — suvy, May 06 '17 at 02:56

score 1 · Accepted Answer · answered May 06 '17 at 02:35

1

You can use the format() function in Python.

"{0:.2f}".format(round(52.003, 2))

You can also use the string formatting operator.

'%.2f' % 52.003

answered May 06 '17 at 02:35

Nick Weseman

Thank you. I do wish there was a way to do it without having to convert it to a string though. – Dman42 May 06 '17 at 02:41
1

@Dman42 to view an value, it is *always* converted to a string, the default just wasn't what you wanted. – Mark Tolonen May 06 '17 at 02:55

score 0 · Answer 2 · answered May 06 '17 at 02:37

0

You can modify the output format like this:

a = 52.003
print "%.2f" % a

answered May 06 '17 at 02:37

lta

score 0 · Answer 3 · answered Jun 21 '17 at 14:17

0

Try this function :

import numpy as np
Round = lambda x, n: eval('"%.' + str(int(n)) + 'f" % ' + repr(x))
a = Round(52.003,2)
print a
>>> 52.00

Just indicate the number of decimals you want as a kwarg. However the result will be a string.

answered Jun 21 '17 at 14:17

Ludovic Aphtes

3 Answers3