How to insert variable containing a path into sed

Question

I'm writing a linux script, which is to replace a string for a file. Here is my script:

#!/bin/sh
var=./video/example.mp4
`sed -i '' 's/sceneFilePath:.*/sceneFilePath: "$var",/g' test`

In the file named test, there is a line like this:

sceneFilePath: "t.mp4",

What I need is to replace this line with the line below:

sceneFilePath: "./video/example.mp4",

It means that things between double quotes should be replaced by the $var.

However when I execute my script, I get sceneFilePath: "$var",.

However, I get an error:

sed: 1: "s/sceneFilePath:.*/scen ...": bad flag in substitute command: 'v'

Use different delimiters in sed which don't appear in you filepaths/names. `s#somthing#$var#`. You probably don't need to `g` flag either. You also don't need to run it in a subshell using `\`\``. You can run the command as is. — 123, May 09 '17 at 10:41

score 0 · Accepted Answer · edited May 09 '17 at 11:23

0

var='.\/video\/example.mp4'
sed -i '' "s/sceneFilePath:.*/sceneFilePath: \"$var\",/g" test

Else:

var='./video/example.mp4'
sed -i '' "s#sceneFilePath:.*#sceneFilePath: \"$var\",#g" test

edited May 09 '17 at 11:23

chepner

answered May 09 '17 at 10:43

Arjun Mathew Dan

1 Answers1