Allocation of memory for a pointer to a structure in C

Asked May 09 '17 at 13:10

Active May 09 '17 at 13:14

Viewed 37 times

When I allocate memory for a structure in C using the malloc function, why don't I have to cast the function since its returning type is void* and not the structure I want? So why this:

Str *str = malloc(sizeof(Str));

and not this:

Str *str = (Str*)malloc(sizeof(Str));

edited May 09 '17 at 13:14

asked May 09 '17 at 13:10

Piddy

Why do you wrap your `malloc` calls in additional parenthesis? – Ben Steffan May 09 '17 at 13:11
Sidenote: `Str* str = (malloc(sizeof(Str));` -> `Str* str = malloc(sizeof(Str));` – Jabberwocky May 09 '17 at 13:11
2

In c, (void *) can be converted to any other pointer type without an explicit cast. This the cast is not necessary in this case – Kram May 09 '17 at 13:18

Allocation of memory for a pointer to a structure in C

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