int main() {
char txt[] = "abcdefghij";
char *pointer = &txt[1];
/* 1*/ printf("%p\n", txt); //0060FF21
/* 2*/ printf("%p\n", &pointer[0]); //0060FF26
/* 3*/ printf("%c\n", *pointer); //b
/* 4*/ printf("%p\n", pointer + 3); //0060FF25
/* 5*/ printf("%c\n", *(pointer + 1 - 1)); //b
/* 6*/ printf("%p\n", ++pointer); //0060FF23
/* 7*/ printf("%c\n", *++pointer); //d
/* 8*/ printf("%p\n", pointer); //0060FF24
/* 9*/ printf("%c\n", --(*pointer)); //c
/*10*/ printf("test %c\n", *pointer); //test c
/*11*/ printf("%c\n", *pointer++); //c
/*12*/ printf("test %c\n", *pointer); //test e <- why ?
/*13*/ printf("%c\n", *(&pointer[1] - 1)); //e
/*14*/ printf("%c\n", *(pointer - 3)); //b
/*15*/ printf("%c\n", *pointer); //e
/*16*/ printf("%c\n", pointer[-1]); //c
/*17*/ printf("%c\n", (pointer + 1)[-1]); //e
/*18*/ printf("%ld\n", pointer - txt); //4
return( EXIT_SUCCESS );
}
I wanted to ask, why the *pointer at /*10*/ printf is c, then the operation *pointer++ (/*11*/ printf) prints c again, but then *pointer is e.
It makes no sense in my mind. I thought
*pointer++ means *(pointer++), so pointer++ would be the address of d, and *(pointer++) would print d.
What am I doing wrong?
