Is using parseInt extraenous if unnecessary?

Question

I am a beginner to coding and JavaScript but I am doing a practice exercise and I came across something I am unsure about.

var nameLength = parseInt(fullName.length);
var nameLength = fullName.length;

I used the first line not even thinking it would already be an integer, so should I still have included the parseInt or not?

No, why would you parse an integer if it's already an integer? — Andrew Li, May 10 '17 at 01:28
`parseInt` should only be called on strings. So what is `fullname.length`? — Bergi, May 10 '17 at 01:29

score 1 · Accepted Answer · answered May 10 '17 at 01:41

Yes, remove var nameLength = parseInt(fullName.length); Below is your explanation:
The parseInt() method in JavaScript is used to turn the integer value of a string into an integer. If I have string, say var s = "3";, I could use the + operator to it, but it wouldn't add as if they were numbers (ex. s += 9;, then s would equal "39"). You call the parseInt() method only if you have a value with the type of string. In your case, and in most, if not all languages, the .length or .length() of anything will return an integer. What you're doing is trying to convert a number to a number, which is (after I googled the definition) extraneous.

Haha, I'm better at vocabulary than coding it would seem. This is exactly what I was looking for thanks @AlexJone — Rob Hudson, May 10 '17 at 02:20

Is using parseInt extraenous if unnecessary?

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