How to search for a specific string of character in another string

Question

i have the following in my code.

String viit = "android.permission.READ_SOCIAL_STREAM";

and

String biit = "READ";

How do i search if viit contains biit?

Please note that viit is not a sentence but more like a word.

if viit **contains** biit - yeah that will do it https://docs.oracle.com/javase/7/docs/api/java/lang/String.html#contains(java.lang.CharSequence) — Scary Wombat, May 10 '17 at 08:01
I think you could put into the question more details if you want — The Bitman, May 10 '17 at 08:01
@vica you can use java string contains() method searches the sequence of characters in this string. It returns true if sequence of char values are found in this string otherwise false. — Rameshbabu, May 10 '17 at 08:03
Possible duplicate of [How to search the whole string for a specific word?](http://stackoverflow.com/questions/10740493/how-to-search-the-whole-string-for-a-specific-word) — Ahtsham Abbasi, May 10 '17 at 08:16

GhostCat · Answer 1 · 2017-05-10T08:04:11.193

4

Simple: you use one of the many methods on String, such as contains().

if (viit.contains(biit)) {

which will give true for an "exact" match. If you need something "more fuzzy", you would be turning to matches() fore example which takes a regular expression. Those allow for a great deal of "fine tuned" patterns to be used.

edited May 10 '17 at 08:04

answered May 10 '17 at 08:02

GhostCat

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Then you want to rework your question and put up a [mcve]. Because then you are doing something wrong ;-) – GhostCat May 10 '17 at 08:04

score 0 · Answer 2 · answered May 10 '17 at 08:03

0

Use contains method.

String viit = "android.permission.READ_SOCIAL_STREAM"; 
String biit = "READ";
if(viit.contains(biit)) {
   //int index = viit.indexOf(biit);
}

https://developer.android.com/reference/java/lang/String.html

answered May 10 '17 at 08:03

PEHLAJ

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Wep0n · Answer 3 · 2017-05-10T08:28:45.083

0

Use the java String.indexOf() method.

In your example, this would be something like that:

boolean hit = viit.indexOf(biit) == -1 ? true : false;

You can omit the boolean if you don't need it, if indexOf has no hit it will return -1.

Or use the String.contains() method which gives a boolean straight away.

edited May 10 '17 at 08:28

answered May 10 '17 at 08:03

Wep0n

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Be careful about using :: like this. In 2017 :: looks like a method refernce; which is probably not want you mean here. – GhostCat May 10 '17 at 08:05
It's meant to be referring to a method, sorry. I've been working with PHP a little bit and they document all their methods this way. Is there a standard pseudo-code or otherwise widely-used way to do this? – Wep0n May 10 '17 at 08:24
Nevermind, I edited my answer, that was a stupid comment on my side – Wep0n May 10 '17 at 08:29

score 0 · Answer 4 · answered May 10 '17 at 08:06

0

You can try to find the string like below

if( string.indexOf("READ") >= 0 ) { 
   Log.i("available", "true");
}else {
   Log.i("not available", "false");
}

answered May 10 '17 at 08:06

Rameshbabu

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score 0 · Answer 5 · answered May 10 '17 at 08:07

0

you can also use String indexOf method. the contains method uses indexof underneath.

regards

answered May 10 '17 at 08:07

Türkmen Mustafa Demirci

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How to search for a specific string of character in another string

5 Answers5