How to accept a vector of strings where strings have spaces in them

Question

My code

#include<iostream>
#include<string>
#include<vector>

using namespace std;

int main(){
    int s;
    cin>>s;
    vector<string> v(s);
    for(int i=0;i<s;i++){
        getline(cin,v[i]);
    }
    cout<<v[1]<<endl;
    return 0;
}

I want to accept an array of strings where strings have spaces in them. The above program doesn't work as it terminates before the loop ends and instead of the second string in the vector v[1] it prints first v[0] no matter what the value of int s is.

Can anyone explain why this is happening and how can I correctly accept an array of strings with spaces?

It *does* print `v[1]`, it's just that `v[1]` is not the string you expect it to be. — molbdnilo, May 10 '17 at 14:36
@stark That statement is outside the loop, `i` is not defined there. Perhaps OP just wants to print the 2nd word. — François Andrieux, May 10 '17 at 14:37
http://stackoverflow.com/questions/5739937/using-getlinecin-s-after-cin — stark, May 10 '17 at 14:40
@stark I am using just for testing purpose. But it still doesn't display `v[1]`, displays `v[0]` and the loop runs one time less than it actually should. For example if s=2 loop runs once and displays `v[0]`, if `s=3` loop runs twice and still displays` v[0]` — gamedev90, May 10 '17 at 14:40
@GameDev90 No, `v[0]` is the empty string. [Illustration](http://ideone.com/2MPlNM). — molbdnilo, May 10 '17 at 14:45

PentaKon · Answer 1 · 2017-05-10T14:49:27.463

0

Use cin.ignore(INTEGER_MAX, '\n'); before each getline statement to clear the cin buffer.

edited May 10 '17 at 14:49

answered May 10 '17 at 14:44

PentaKon

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How to accept a vector of strings where strings have spaces in them

1 Answers1