Post Multipart and Json together with Guzzle in Laravel

Question

I'm trying to POST multipart and json data with Guzzle to build my apps with Phonegap Build API. I've tried many adjustment but still got error results. Here's the latest function I'm using:

public function testBuild(Request $request)
{
     $zip_path = storage_path('zip/testing.zip');
     $upload = $this->client->request('POST', 'apps',
          ['json' =>
            ['data' => array(
              'title'         => $request->title,
              'create_method' => 'file',
              'share'         => 'true',
              'private'       => 'false',
            )],
           'multipart' => 
            ['name'           => 'file',
             'contents'       => fopen($zip_path, 'r')
            ]
          ]);
      $result = $upload->getBody();
      return $result;
}

This is my the correct curl format that has success result from the API, but with file I have in my desktop:

curl -F file=@/Users/dedenbangkit/Desktop/testing.zip 
-u email@email.com 
-F 'data={"title":"API V1 App","version":"0.1.0","create_method":"file"}'
 https://build.phonegap.com/api/v1/apps

`This option cannot be used with body, form_params, or json` from http://docs.guzzlephp.org/en/latest/request-options.html#multipart — cre8, May 12 '17 at 07:54
Then what your suggestion? should I revert this post to normal CURL post? — Deden Bangkit, May 12 '17 at 08:13
maybe this helps: http://stackoverflow.com/questions/38133244/upload-file-using-guzzle-6-to-api-endpoint — cre8, May 12 '17 at 08:32

score 5 · Accepted Answer · answered May 12 '17 at 09:48

5

As mentioned before, you cannot use multipart and json together.

In your curl example it's just a multipart form, so use the same in Guzzle:

$this->client->request('POST', 'apps', [
    'multipart' => [
        [
            'name' => 'file',
            'contents' => fopen($zip_path, 'r'),
        ],
        [
            'name' => 'data',
            'contents' => json_encode(
                [
                    'title' => $request->title,
                    'create_method' => 'file',
                    'share' => 'true',
                    'private' => 'false',
                ]
            ),
        ]
    ]
]);

answered May 12 '17 at 09:48

Alexey Shokov

4,775
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Thank you, your code works for me. But why array didn't work for the contents data? – Deden Bangkit May 12 '17 at 09:56
1

Because `contents` is (simply) a byte array. `json` in Guzzle is just a small fancy helper that does `json_encode()` for you, but it works only for "simple" bodies, multipart option doesn't have such helper. – Alexey Shokov May 12 '17 at 10:06
Got it, now I understand how guzzle works. Thanks a ton! – Deden Bangkit May 12 '17 at 19:19

Post Multipart and Json together with Guzzle in Laravel

1 Answers1