Java get timer from specific date to current date

Question

So I have this code right now:

long diff = dateTwo.getTime() - dateOne.getTime();
long seconds = diff/1000;
long minutes = seconds/60;
long hours = minutes/60;
long days = hours/24;
long years = days/365;

And this gets me the elapsed time in minutes, seconds, days and years, but I want to have a timer that shows something like: Time passed - 1 year, 20 days, 5 minutes, 20 seconds. How can I make an algorithm that takes into account leap years and displays the numbers correctly?

If you use Java 8 then look into the new date and time library. It is very easy to do this. — Thorbjørn Ravn Andersen, May 14 '17 at 18:17
Can you point me to a link, please? I searched the internet but haven't stumbled upon anything — ubuntuaskdanidani, May 14 '17 at 18:19
[link](http://www.oracle.com/technetwork/articles/java/jf14-date-time-2125367.html) and [this one as well](https://docs.oracle.com/javase/8/docs/api/java/time/package-summary.html) — Bill F, May 14 '17 at 18:20
You can use the newer `java.time` classes from JSR-310 on Android alright, @ThorbjørnRavnAndersen. See [this question: How to use ThreeTenABP in Android Project](http://stackoverflow.com/questions/38922754/how-to-use-threetenabp-in-android-project) and its great and thorough answer. — Ole V.V., May 14 '17 at 19:29
@ubuntuaskdanidani, do you want months too (if there are any)? I take it from your example that you don’t want weeks. — Ole V.V., May 15 '17 at 07:26

Yan.F · Answer 1 · 2017-05-14T19:14:37.890

2

You can use the getters of java.time.LocalDateTime for that.

LocalDateTime now = LocalDateTime.now();
LocalDateTime past = LocalDateTime.of(someYear,someMonth...)
int year = now.getYear() - past.gerYear();
int month = now.getMonthValue() - past.getMonthValue();
int day = now.getDayOfMonth() - past.getDayOfMonth();
int hour = now.getHour() - past.getDayOfHour();
int minute = now.getMinute() - past.getMinute();
int second = now.getSecond() -past.getSecond();
int millis = now.get(ChronoField.MILLI_OF_SECOND) - past.get(ChronoField.MILLI_OF_SECOND);

notice that you need to use some if else statements to check which value is bigger and subtract from it the other

edited May 14 '17 at 19:14

answered May 14 '17 at 18:36

Yan.F

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What if you want to know from 2016-11-13 to 2017-01-01? – Thorbjørn Ravn Andersen May 14 '17 at 19:04
LocalDateTime x = LocalDateTime.of(2017, 1,1, 0, 0); LocalDateTime y = LocalDateTime.of(2016, 11,13 , 0, 0); int year = x.getYear() - y,getYear(); .... and so on.. notice that you need to use some if else statements to check which value is bigger and subtract from it the other. – Yan.F May 14 '17 at 19:10
Considered using a duration or period instead? – Thorbjørn Ravn Andersen May 14 '17 at 19:32

score 2 · Answer 2 · answered May 14 '17 at 19:09

I ended up doing this:

 diff = dataDoi.getTime() - dataPrima.getTime();
 x = TimeUnit.MILLISECONDS.toSeconds(diff);
 seconds = x % 60;
 x /= 60;
 minutes = x % 60;
 x /= 60;
 hours = x % 24;
 x /= 24;
 days = x % 365;
 x /= 365;
 years = x;

By diving every time, you get the remaining time only.

score 1 · Answer 3 · answered May 14 '17 at 18:25

1

You need to check result of dividing years of 4 because when leap years divide on 4 we will have 0:

if(years % 4 == 0) {
 // to do something
}

answered May 14 '17 at 18:25

Vasyl Lyashkevych

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Java get timer from specific date to current date

3 Answers3