Spring get clicked button in Java-Class

Question

I have following problem: I have two buttons accept and decline. In my Controller-Class i want to know, which button were clicked. i solved this in a way, which is bad i think. Each button got his own form, so that i can see which button was triggered.

<form method="post" action="save">
    <input type="hidden" name="accept" th:value="true" />
    <button type="submit" name="accepted" id="modalAcceptTrigger"
        class="btn btn-lg myBtn_accept" title="Auftrag annehmen">
        Annehmen
    </button>
</form>
<form method="post" action="save">
    <input type="hidden" name="decline" th:value="false" />
    <button type="submit" name="declined" id="modalDeclineTrigger"
        class="btn btn-lg myBtn_decline" title="Auftrag abgelehnt">
        Ablehnen
    </button>
</form>

In my class i get the hidden input field and know which button was pressed.

@PostMapping("/save")
public String saveJob(@RequestParam(value = "accept") Boolean accept) {

    if (accept) {
        ...
    } else {
        ...
    }
}

My question is now: How can i make only one form and get the triggered button in my java class? Does anybody know and can help me?

Possible duplicate of http://stackoverflow.com/questions/8954426/spring-mvc-multiple-submit-button-to-a-form — M. Haverbier, May 15 '17 at 09:40

score 2 · Accepted Answer · answered May 15 '17 at 09:39

I would have just have one form with 2 buttons as you say. Before submitting the form I would have a js function executed that changes the input hidden value decline/accept. So I would

<form method="post" id="save-form" action="save">
    <input type="hidden" id="action" name="action" />
    <button type="button" name="declined" id="modalDeclineTrigger"
        class="btn btn-lg myBtn_decline" title="Auftrag abgelehnt">
        Ablehnen
    </button>
    <button type="button" name="accepted" id="modalAcceptTrigger"
        class="btn btn-lg myBtn_accept" title="Auftrag annehmen">
        Annehmen
    </button>
</form>

And the js: (That should be place within an on document ready)

<script>
$('#modalAcceptTrigger').on('click', function(){$('#action').val('decline'); $('#save-form').submit();});
$('#modalDeclineTrigger').on('click', function(){$('#action').val('accept'); $('#save-form').submit();});
</script>

And the controller should expect an ENUM {decline, accept} rather than a boolean

Thank you for the reply. It works, but it is not an ENUM in the controller, but a String. — Anton Styopin, May 15 '17 at 10:13

score 1 · Answer 2 · edited May 23 '17 at 12:34

1

Leave just one form with hidden input

<input type="hidden" name="userAction" th:value="true" />

add a script to set the userAction to true or false depending on clicked option before submitting form (see e.g. here).

and in the controller

@PostMapping("/save")
public String saveJob(@RequestParam(value = "userAction") Boolean accept)

edited May 23 '17 at 12:34

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answered May 15 '17 at 09:34

StanislavL

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Thanks for answering, i will try! – Anton Styopin May 15 '17 at 09:36

Spring get clicked button in Java-Class

2 Answers2