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I want to write a program that rolls a dice. Now this is what I have :

import random
print("You rolled",random.randint(1,6))

And I also want to be able to do something like this:

print("Do you want to roll again? Y/N")

and then if I press Y it rolls again and if I press N I quit the app. Thanks in advance!

6 Answers6

13

Let's walk through the process: You already know what you need to generate random numbers.

  1. import random (or you could be more specific and say from random import randint, because we only need randint in this program)
  2. As you've already said it; print("You rolled",random.randint(1,6)) "rolls the dice". but it does it only once, so you need a loop to repeat it. A while loop is calling to us.
  3. You need to check if the user inputs Y. And you can simply do it with "Y" in input().

code version 1. 

import random
repeat = True
while repeat:
    print("You rolled",random.randint(1,6))
    print("Do you want to roll again? Y/N")
    repeat = "Y" in input()

code version 1.1 (A little better)

from random import randint
repeat = True
while repeat:
    print("You rolled",randint(1,6))
    print("Do you want to roll again?")
    repeat = ("y" or "yes") in input().lower()

In this code, the user is free to use strings like yEs, y, yes, YES and ... to continue the loop.

Now remember, in version 1.1, since I used from random import randint instead of import random, I don't need to say random.randint(1, 6) and simply radint(1,6) will do the job.

Vinícius Figueiredo
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Amir Shabani
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-1
import random
min = 1
max = 6

roll_again = "yes"
 roll_again = raw_input

while roll_again == "yes" or roll_again == "y":
    print ("Rolling the dices...")
    print ("The values are....")
    print (random.randint(min, max))
    print (random.randint(min, max))

    roll_again = raw_input("Roll the dices again?")
Kaitlyn Harley
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user9184791
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This is for python 3

import random
repeat="Y"
while repeat == "Y":
   print("Rolling the dice")
   print(random.randint(1,6))

repeat =input("Do you wanna roll again Y/N?")
if repeat=="Y":
    continue
Dipin
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    This looks very similar to the existing answers, so you should elaborate what makes it better. Also, code-only answers are generally frowned upon. – Jens Bannmann Mar 17 '18 at 11:27
-1

I just started learning Python three days ago, but this is what I came up with for Python 3, and it works:

import random

question = input('Would you like to roll the dice [y/n]?\n')

while question != 'n':
    if question == 'y':
        die1 = random.randint(1, 6)
        die2 = random.randint(1, 6)
        print(die1, die2)
        question = input('Would you like to roll the dice [y/n]?\n')
    else:
        print('Invalid response. Please type "y" or "n".')
        question = input('Would you like to roll the dice [y/n]?\n')        

print('Good-bye!')
Rick Wohlschlag
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-1
from random import randint
ques = input('Do you want to dice Y/N : ')

while ques.upper() == 'Y':
    print(f'your number is {randint(1,6)}')
    ques = input('Do you want to roll again !!')
else:
    print('Thank you For Playing')
Samiksha
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-1
import random
def dice_simulate():
    number = random.randint(1,6)
    print(number)
    while(1):
       flag = str(input("Do you want to dice it up again:Enter 1 and if not enter    0"))
       if flag == '1':
         number = random.randint(1,6)
         print(number)
      else:
         print("ending the game")
         return

dice_simulate()

For more understanding you can refre this: https://community.progress.com/code_share_group/f/169/t/35797

Preeti Duhan
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  • Do not use `while(1):`; Python idiom is to use `while True:`, `while` is not a function nor do Python compound statements use parentheses. You have 2 `random.randint()` calls in the code, that can trivially be reduced to one. This example is certainly no better than the other, earlier answers to this question. – Martijn Pieters Feb 22 '21 at 12:55