how to get notified when a process wants to open a file?

Asked May 16 '17 at 20:29

Active May 16 '17 at 20:30

Viewed 257 times

I want to write a program that will be notified and do a certain event each time a process wants to open a file, and will we able to allow the process access to a new file or disallow it.
For example: I want it to work like the fanotify API in linux.
Is there any way to do the same thing under windows ?

I want it to notify me when the OpenFile or CreateFile or other functions that work with files run: CreateFile Example

edited May 16 '17 at 20:30

asked May 16 '17 at 20:29

shaked nissanov

5

write minifilter driver – RbMm May 16 '17 at 20:30
Or buy a third-party file system filter driver, or use API hooking. Depends on your circumstances, really. – Harry Johnston May 16 '17 at 23:41
Possible duplicate of [Intercept windows open file](http://stackoverflow.com/questions/1109564/intercept-windows-open-file) – Raymond Chen May 17 '17 at 13:53

how to get notified when a process wants to open a file?

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