Bash - Parse a String Into Array separated with comma

Question

in Bash, how can i transform below string in an array in Bash:

details="cl roo,dara shi,GD leader, is the man,YG FAMILY"

This is my code:

IFS="[a-z],[a-z]" read -r -a details_list <<< "$details"

Expected output when array is iterated:

cl roo
dara shii
GD leader, is the man
YG FAMILY

Actual Output when array is iterated:

cl roo
dara shii
GD leader
is the man
YG FAMILY

Duplicate question: Here's [a link](http://stackoverflow.com/a/10586169/5612294)! — odarboe, May 18 '17 at 08:14
I've checked it and it is different from the Expected output. — stickyservernotes, May 18 '17 at 08:26
I was thinking thebdelimiter is a comma that is placed between two characters.... i don't know how to work it on regex. — stickyservernotes, May 18 '17 at 08:33

FrankTheTank_12345 · Answer 1 · 2017-05-18T08:30:57.917

0

This should works:

details="cl roo;dara shi;GD leader, is the man;YG FAMILY"

IFS=';' read -r -a array <<< "$details"

echo "${array[2]}"   -> GD leader, is the man

edited May 18 '17 at 08:30

answered May 18 '17 at 08:20

Thank you for your answer. I have tried this but "GD leader, is the man" was cut in two. I want to put it in one index. – stickyservernotes May 18 '17 at 08:24
@stickyservernotes: Look at my edit. 'GD leader' is in one – FrankTheTank_12345 May 18 '17 at 08:26
@stickyservernotes now it works. Please use another seperator like ';' – FrankTheTank_12345 May 18 '17 at 08:31
I am saving this as the last resort. The string i am going to parse will be from a logfile so i can't change the separator as I like. – stickyservernotes May 18 '17 at 08:37

1 Answers1