Convert datetime object into milliseconds

Question

This has probably been asked like a million times, but I still didn't manage to do it.

The case is, that I need to calculate the time between two unix timestamps:

eg: 1494708797619 - 1494709197066

What I have so far:

from datetime import datetime
a = datetime.fromtimestamp(1494708797619/1000.0)
b = datetime.fromtimestamp(1494709197066/1000.0)
c = b-a
print(c)

But the answer is currently in datetime format like that:

0:06:39.447000

But I'd like it to be something like that:

399447000

Cheers!

If you just want the result in seconds, why are you converting to datetime at all? Why not just `1494708797619 - 1494709197066`? — Daniel Roseman, May 19 '17 at 13:26
[This answer](http://stackoverflow.com/a/18426915/1971805) will prob be of help — TerryA, May 19 '17 at 13:27

score 2 · Accepted Answer · answered May 19 '17 at 13:34

from datetime import datetime
a = datetime.fromtimestamp(1494708797619/1000.0)
b = datetime.fromtimestamp(1494709197066/1000.0)
c = int((b-a).total_seconds() * 1000)
print(c)

Will output

But shortest way will be 1494708797619 - 1494709197066 as Daniel noted

score 1 · Answer 2 · answered May 19 '17 at 13:29

1

A timedelta object (which is what you get when you add/subtract two datetime or date objects) has a .total_seconds() method which returns the total seconds. Just multiply that by 1000.

c = b-a
c.total_seconds() * 1000

answered May 19 '17 at 13:29

panatale1

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Convert datetime object into milliseconds

2 Answers2