Calling functions in functions - Python

Question

How would I go about to get this to work? I've searched but I can't get it to work still. Should I just put the a() function in the b function even if I add more variables?

counter = 1

def a():
    az = 1
    bz = 2
    cz = 3

def b():
    a()
    if counter > 0 :
        print az, bz, cz

b()

The variable in function `a()` is *local* to the function `a()`, can't be accessed in function `b()`. — zhenguoli, May 20 '17 at 02:51
This should be useful to you: http://stackoverflow.com/questions/291978/short-description-of-the-scoping-rules — fileyfood500, May 20 '17 at 02:52
The point is, `a()` is being called correctly in b, but the variables in a don't exist in b. — fileyfood500, May 20 '17 at 02:54

score 1 · Accepted Answer · edited May 23 '17 at 11:47

1

Alright, you need to understand the concept of scope. az, bz and cz are known only inside your function a(). So you can't print their values inside function b(). You could do something like:

counter = 1

def a():
    az = 1
    bz = 2
    cz = 3
    if counter > 0 :
        print az, bz, cz

def b():
    a()

b()

And as @fileyfood500 said in his comment, you might want to read this.

edited May 23 '17 at 11:47

Community

1
1

answered May 20 '17 at 02:54

rbock

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5
15

score 0 · Answer 2 · answered May 20 '17 at 02:56

0

One potential fix is to return the values from a.

counter = 1

def a():
    az = 1
    bz = 2
    cz = 3
    return(az,bz,cz)

def b():
    (az,bz,cz) = a()
    if counter > 0 :
        print az, bz, cz

b()

answered May 20 '17 at 02:56

fileyfood500

1,199
1
13
29

Calling functions in functions - Python

2 Answers2