unique
unlike sum
is a free function only and not a class (instance to be precise) method. The difference between the two is
obj.foo() # instance method, obj is implicitly passed to foo()
foo(obj) # free function, obj is explicity passed to foo()
Have a look here for some explanation on different variants of methods. In NumPy, this is mainly a design decision, I believe, however there are certain reasons for some functions to be a free function. One reason that comes to mind, is that unlike in other technical languages (such as MATLAB), numpy arrays can be structured or unstructured and can be flexible in terms of containing objects of different types, for example
a = np.array([[1,2],[3,4]]) # structured array
b = np.array([[1,2],[3,4,5]]) # unstructured array
c = np.array([[1,2],["abc",True]]) # unstructured array with flexible data type
In such scenarios, having to make every function/method an instance method, would lead to confusing behaviour. Even the sum
function behaves differently with structured and unstructured arrays
In [18]: a.sum() # sums all elements of the array
Out[18]: 10
In [19]: b.sum() # concatenates all elements of the array
Out[19]: [1, 2, 3, 4, 5]
In contrast, some functions like unique
have a much narrower scope in terms of their applications. For example unique
only works for structured arrays/buffers of uniform data type and operates on the flattened (1D dimensional) version of the arrays.
attributes
of numpy arrays typically tell you about the underlying data type, shape, dimensionality, memory layout/strides and data ownership of the array, for instance:
In [20]: a=np.random.rand(3,4)
In [21]: a.flags
Out[21]:
C_CONTIGUOUS : True
F_CONTIGUOUS : False
OWNDATA : True
WRITEABLE : True
ALIGNED : True
UPDATEIFCOPY : False
In [22]: a.shape
Out[22]: (3, 4)
In [23]: a.dtype
Out[23]: dtype('float64')
are all attributes
and not array methods per say, in other words they are properties.