Symfony 2.8 - forms fields depending on user status

Question

I am wondering how to solve this problem: I have form with 4 fields. I want 4th field to be dependent on user status (logged or unlogged). For logged user I will get ID from session but unlogged user should provide username manually.

I dont know which option should i use. Inherit_data, two form types (two much duplicated code) or validation groups based on the submitted data. Any ideas?

it's not clear what exactly you'd like to be different? Different form types like if logged in than hidden-field with token and when not - dropdown with all available usernames ? — V-Light, May 22 '17 at 11:07
@V-Light validation will be different for this two cases. For logged in user there is no field "username" - only hidden field "user". But for unlogged field "username" (which is text field) is required. I dont know how to create this two forms using only one form builder. — symfonydevpl, May 22 '17 at 11:34

score 1 · Accepted Answer · answered May 22 '17 at 11:59

Ok, There are several ways to achive that.

Take a Look at FormEvents. In your case it would be FormEvents::PRE_SET_DATA and then read about dynamic forms

I personly prefer to do following

public function buildForm(FormBuilderInterface $builder, array $options)
{
   //$builder->add( ... )
   //$builder->add( ... )
   //$builder->add( ... )

   //each-event with own method, but of cource it can be a callback like in a tutorial above
   $builder->addEventListener(FormEvents::PRE_SET_DATA, array(this, 'onPreSetData');

}

and in the same class there is a method onPreSetData

public function onPreSetData ( FormEvent $formEvent )
{
    $form = $formEvent->getForm();
    $user = $formEvent->getData();

    //pseudo-code
    if( $user->isLoggedIn() )
    {
        $form->add('user', HiddenType::class, array(

        ));
    }
    else
    {
        $form->add('user', TextType::class, array(
            'label' => 'Username',
            'required' => true,
            'constraints' => array(
                new NotBlank(array('message' => 'please enter username...')),
                // new YourCustomValidator(array('message' => 'not enough minerals...')),
            )
        ));
    }
}

Thank you, this is exactly what i was looking for :) – symfonydevpl May 22 '17 at 12:01 — symfonydevpl, May 22 '17 at 12:01

score 1 · Answer 2 · answered May 23 '17 at 09:48

1

I personally think a more elegant solution is to pass the user to the form builder from your controller. It's been covered in this answer here: how to check the user role inside form builder in Symfony2?

answered May 23 '17 at 09:48

OK sure

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score 0 · Answer 3 · answered May 22 '17 at 11:21

0

you can create form by individual fields like

 {{ form_row(form.username) }}                           
 {{ form_row(form.email) }}                           
 {{ form_row(form.phone) }} 
 {% if(app.user) %}
     //your conditional field
 {% endif%}

By this way, you have to create submit button as well as csrf token if there

I hope this will quite helpful :)

answered May 22 '17 at 11:21

Jaysukh Maghodiya

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I know about creating individual fields. I can display fields depending on user status, but i cant validate them properly. If logged in user will submit the form, he will see error which says that "username" fields is required, because i want to use only one FormBuilder class – symfonydevpl May 22 '17 at 11:39

Symfony 2.8 - forms fields depending on user status

3 Answers3