Remove trailing zeros after the decimal point in Python

Question

I am using Python 2.7. I need to replace "0" string at the end.

Say, a = "2.50":

 a = a.replace('0', '')

I get a = 2.5, and I am fine with this result.

Now a = "200":

 a = a.replace('0', '')

I get a = 2, and this output is as per design I agreed. But I expect the output a = 200.

Actually what I am looking is

when any value after decimal point at the end is "0" replace that "0" with None value.

Below are the examples and I am expecting results.

IN: a = "200"
Out: a = 200
In: a = "150"
Out: a = 150
In: a = 2.50
Out: a = 2.5
In: a = "1500"
Out: a = 1500
In: a = "1500.80"
Out: a = 1500.8
In: a = "1000.50"
Out: a = 1000.5

Not a value is string.

Note: sometimes a = 100LL or a = 100.50mt.

Possible duplicate of [drop trailing zeros from decimal](http://stackoverflow.com/questions/11227620/drop-trailing-zeros-from-decimal) — WhatsThePoint, May 22 '17 at 11:02
assuming the `a` type is `str` then you could use `s[-1]`, so that it only grab the last character in the string. — arnold, May 22 '17 at 11:04
@WhatsThePoint: the specifications have changed: there can be additional tailing text. — Willem Van Onsem, May 22 '17 at 12:26
@WillemVanOnsem ughhh well i guess that happens when not all info is given from the start :/ — WhatsThePoint, May 22 '17 at 12:28

Willem Van Onsem · Answer 1 · 2017-05-24T14:48:29.323

5

You can do this using a regular expression:

import re

rgx = re.compile(r'(?:(\.)|(\.\d*?[1-9]\d*?))0+(?=\b|[^0-9])')

b = rgx.sub('\2',a)

Where b is the result of removing tailing zeros after the decimal point from a.

We can write this in a nice function:

import re

tail_dot_rgx = re.compile(r'(?:(\.)|(\.\d*?[1-9]\d*?))0+(?=\b|[^0-9])')

def remove_tail_dot_zeros(a):
    return tail_dot_rgx.sub(r'\2',a)

And now we can test this:

>>> remove_tail_dot_zeros('2.00')
'2'
>>> remove_tail_dot_zeros('200')
'200'
>>> remove_tail_dot_zeros('150')
'150'
>>> remove_tail_dot_zeros('2.59')
'2.59'
>>> remove_tail_dot_zeros('2.50')
'2.5'
>>> remove_tail_dot_zeros('2.500')
'2.5'
>>> remove_tail_dot_zeros('2.000')
'2'
>>> remove_tail_dot_zeros('2.0001')
'2.0001'
>>> remove_tail_dot_zeros('1500')
'1500'
>>> remove_tail_dot_zeros('1500.80')
'1500.8'
>>> remove_tail_dot_zeros('1000.50')
'1000.5'
>>> remove_tail_dot_zeros('200.50mt')
'200.5mt'
>>> remove_tail_dot_zeros('200.00mt')
'200mt'

edited May 24 '17 at 14:48

answered May 22 '17 at 11:01

Willem Van Onsem

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sorry I did not update in question now i Have updated. This will not work remove_tail_dot_zeros('200.50mt') – kitty May 22 '17 at 12:13
Sir, I got issue again i get a value like remove_tail_dot_zeros('200.00000mt') and I got output like 200.mt any fix? – kitty May 22 '17 at 16:01
@kitty: you want one zero? Please next time add specifications for *corner cases* to your question. – Willem Van Onsem May 22 '17 at 16:01
No Zero required at end sir, with this remove_tail_dot_zeros('200.00000mt'). I get 200.mt this dot is not required. This earlier not noticed after testing I have noticed it. – kitty May 24 '17 at 14:00
So you want to remove the decimal dot? – Willem Van Onsem May 24 '17 at 14:01
Yes exactly sir – kitty May 24 '17 at 14:23
@kitty: updated. Can you please in future provide full specifications in your question. This question is hard to answer simply because information is *missing*. – Willem Van Onsem May 24 '17 at 14:49
Sure, Thanks and your points to be noted sir. Future i will provide full info – kitty May 24 '17 at 15:57

score 2 · Answer 2 · answered May 22 '17 at 11:11

2

Look for '.' in the item and them decide to remove the trailing (right-side) zero:

>>> nums = ['200', '150', '2.50', '1500', '1500.80', '100.50']
>>> for n in nums:
...     print n.rstrip('0').rstrip('.') if '.' in n else n
... 
200
150
2.5
1500
1500.8
100.5

answered May 22 '17 at 11:11

Nabeel Ahmed

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sorry I did not update in question now i Have updated. it wont work when value is 250.50mt i need it as 250.5mt – kitty May 22 '17 at 12:19

Muthuraj S · Answer 3 · 2017-05-22T16:25:44.077

0

Try this,

import re

def strip(num):

    string = str(num)
    ext = ''

    if re.search('[a-zA-Z]+',string): 
        ext = str(num)[-2:]
        string = str(num).replace(ext, '')


    data = re.findall('\d+.\d+0$', string)
    if data:
        return data[0][:-1]+ext

    return string+ext

edited May 22 '17 at 16:25

answered May 22 '17 at 11:48

Muthuraj S

107
6

sorry I did not update in question now i Have updated. it wont work when value is 250.50mt i need it as 250.5mt – kitty May 22 '17 at 12:20
Please try this – Muthuraj S May 22 '17 at 13:16
Sir i may get many characters like ll mt kk bb those are not predictable – kitty May 22 '17 at 16:02

Remove trailing zeros after the decimal point in Python

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