extract 7z file using python 3

Question

I was trying to decompress a 7z file using python, but I can't seem to figure it out. I figured I could use the lzma module in python 3, but I can't seem to figure it out:

I thought it would work like the zipfile package:

import lzma
with lzma.open('data.7z') as f:
    f.extractall(r"<output path>")

but after reading the documents, it doesn't seems to. So here is my question: How can you extract a 7z file using the standard package? I don't want to call subprocess to extract the files using 7-zip because I can't guarantee that users have this software installed.

I've searched the internets and stack oerflow and noticed all the answers almost go back to using subprocessing which I would like to avoid like the plague.

Though there are similar questions on stackoverflow, the answers all still depend on 7-zip or the 7zip SDK. I do not want to use the 7-zip sdk/exe for extraction because that assumes the users have the software installed.

Here is the properties from the 7z file:

executing the above code, what output do you get ? any exceptions ? — Nabeel Ahmed, May 23 '17 at 14:04
@NabeelAhmed builtins.AttributeError: 'LZMAFile' object has no attribute 'extractall' — code base 5000, May 23 '17 at 14:34
I think that this might be a duplicate of: [Python3: lzma unpack .7z file](https://stackoverflow.com/questions/31743127/python3-lzma-unpack-7z-file) — pgmank, Sep 22 '17 at 20:41

score 21 · Answer 1 · answered Aug 21 '19 at 10:02

21

What about trying this?:

from pyunpack import Archive
Archive('data.7z').extractall("<output path>")

answered Aug 21 '19 at 10:02

Matt Dnv

1,620
13
23

9

Marvelous, after `pip install pyunpack` and `pip install patool` it worked excellent! – a.t. Aug 21 '20 at 19:13

extract 7z file using python 3

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